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[c++]CHALLENGE FOR ANYONE HO THINKS IS GOOD AT C++ ITS SIMPLE PROGRAM BUT I NEED EXP

by MeSvAk - 11 April, 2020 - 06:59 AM
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#1
SO BASICALLY ITS JUST TO SEE HOW MUCH U KNOW ABOUT C++ AND WHAT U BRAGGING OFFFFFFF 


https://pastr.io/view/pF1AGaYYneV

TELL ME WHAT IT DOES AND WHY DIG IN EXPLANATION
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#2
You don’t know shit
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#3
(This post was last modified: 11 April, 2020 - 07:52 AM by Kirmada. Edit Reason: Full explanation updated )
@MeSvAk

1. It asks user to give a string input
2. it then stores it in the array str1
3. It again asks for another string 
4. It stores it in array str2
5. it defines i, j , flag and uses i and j with str1 and str2 respectively to increment the array element one by one unless it encounters a null string or simply the end of string { because after the input is complete the array will fill all the element with 0 , hence 0 signifies the end of string given by the user. }
6. for(i=0,j=0;str1[i]!='\0',str2[j]!='\0';i++,j++) here it increments array elements one by one for both and then if(str1[i]==str2[j]) code check if any of the element is equal or not.
7. If any single element is equal in both of the string it prints " st a n eq " and if not " st a eq " gets printed

 
Here is a c version for it which checks if any digit is repeted in the integer https://pastr.io/raw/rzuq4Tyhik1

BTW YOUR CODE IS BUGGY
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#4
(11 April, 2020 - 07:05 AM)Kirmada Wrote: Show More
@MeSvAk

1. It asks user to give a string input
2. it then stores it in the array str1
3. It again asks for another string 
4. It stores it in array str2
5. it defines i, j , flag and uses i and j with str1 and str2 respectively to increment the array element one by one unless it encounters a null string or simply the end of string { because after the input is complete the array will fill all the element with 0 , hence 0 signifies the end of string given by the user. }
6. for(i=0,j=0;str1!='\0',str2[j]!='\0';i++,j++) here it increments array elements one by one for both and then if(str1[i]==str2[j]) code check if any of the element is equal or not.
7. If any single element is equal in both of the string it prints " st a n eq " and if not " st a eq " gets printed

 
Here is a c version for it which checks if any digit is repeted in the integer https://pastr.io/raw/rzuq4Tyhik1

BTW YOUR CODE IS BUGGY
[/i]


u possess 69 gz to u ur dad is gay rn u will need to make him pregnant in his anusussusususus  Wooow Wooow Wooow Wooow Wooow [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: Amusing.png] [Image: Amusing.png] [Image: Amusing.png]
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#5
(11 April, 2020 - 08:01 AM)MEsvaK Wrote: Show More
(11 April, 2020 - 07:05 AM)Kirmada Wrote: Show More
@MeSvAk

1. It asks user to give a string input
2. it then stores it in the array str1
3. It again asks for another string 
4. It stores it in array str2
5. it defines i, j , flag and uses i and j with str1 and str2 respectively to increment the array element one by one unless it encounters a null string or simply the end of string { because after the input is complete the array will fill all the element with 0 , hence 0 signifies the end of string given by the user. }
6. for(i=0,j=0;str1!='\0',str2[j]!='\0';i++,j++) here it increments array elements one by one for both and then if(str1[i]==str2[j]) code check if any of the element is equal or not.
7. If any single element is equal in both of the string it prints " st a n eq " and if not " st a eq " gets printed

 
Here is a c version for it which checks if any digit is repeted in the integer https://pastr.io/raw/rzuq4Tyhik1

BTW YOUR CODE IS BUGGY
[/i]


u possess 69 gz to u ur dad is gay rn u will need to make him pregnant in his anusussusususus  Wooow Wooow Wooow Wooow Wooow [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: Amusing.png] [Image: Amusing.png] [Image: Amusing.png]
was it correct ?
                LIKE = SUPPORT 
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                                                                       LIKE || +REP || SUPPORT
         Donate me some credits & help me get the Indian flag 
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#6
(11 April, 2020 - 08:06 AM)Kirmada Wrote: Show More
(11 April, 2020 - 08:01 AM)MEsvaK Wrote: Show More
(11 April, 2020 - 07:05 AM)Kirmada Wrote: Show More
@MeSvAk

1. It asks user to give a string input
2. it then stores it in the array str1
3. It again asks for another string 
4. It stores it in array str2
5. it defines i, j , flag and uses i and j with str1 and str2 respectively to increment the array element one by one unless it encounters a null string or simply the end of string { because after the input is complete the array will fill all the element with 0 , hence 0 signifies the end of string given by the user. }
6. for(i=0,j=0;str1!='\0',str2[j]!='\0';i++,j++) here it increments array elements one by one for both and then if(str1[i]==str2[j]) code check if any of the element is equal or not.
7. If any single element is equal in both of the string it prints " st a n eq " and if not " st a eq " gets printed

 
Here is a c version for it which checks if any digit is repeted in the integer https://pastr.io/raw/rzuq4Tyhik1

BTW YOUR CODE IS BUGGY
[/i]


u possess 69 gz to u ur dad is gay rn u will need to make him pregnant in his anusussusususus  Wooow Wooow Wooow Wooow Wooow [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: monkaEyes.png] [Image: Amusing.png] [Image: Amusing.png] [Image: Amusing.png]
was it correct ?

yes ur explanation is correct but ur c program wont run and it wont get the currect value :) ur line 3  and line seen n = 1 wont work
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#7
It's the worst piece of code I have ever seen in my life. Please never program again.
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